The following describe the OFDMA DL algorithm presented in Section 9.7.
For i=1:# of snapshots
- Distribute sufficiently many UEs randomly throughout the system area such that to each cell within the HO margin of 3 dB the same number K of users is allocated as active UEs.
- Calculate the pathloss from each UE to all cells and find the smallest pathloss
- Link the UE randomly to a cell to which the pathloss is within the smallest pathloss plus the HO margin of 3 dB
- Select K UEs randomly from all the UEs linked to one cell as active UEs. These K active UEs will be scheduled during this snapshot.
- Note: a full load system is assumed, namely, all available resource blocks (RBs) will be allocated to active UEs. And each UE is scheduled with the same number N of RBs. Thus, the BS transmit power per UE is fixed.
- Let
denote the maximum transmit power of BS -
is the number of all available RBs in each cell 
is the transmit power from BS to the active UE, and
.
- Let
2. Calculate DL C/I for all active UEs in all cells.
- Loop over all cells from j=1 to
(the number of cells in the system area e.g. 57 for 19 sites with tri-sector antennas) - Loop over all active UEs from k=1 to K
- For the k-th active UE in the j-th cell (i.e.UE_j,k ) its C/I is denoted by
,
- Loop over all cells from j=1 to
3. Determine the throughput for each UE with its C/I according to the link-to-system level mapping.
4. Collect statistics.