Page Comparison

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1. Distribute sufficiently many UEs randomly throughout the system area such that to each cell within the HO margin of 3 dB the same number  of K of users is allocated as active UEs.

• • Calculate the pathloss from each UE to all cells and find the smallest pathloss
  • Link the UE randomly to a cell to which the pathloss is within the smallest pathloss plus the HO margin of 3 dB
  • Select K UEs randomly from all the UEs linked to one cell as active UEs. These  active K active UEs will be scheduled during this snapshot.
  • Note: a full load system is assumed, namely, all available resource blocks (RBs) will be allocated to active UEs. And each UE is scheduled with the same number  of N of RBs. Thus, the BS transmit power per UE is fixed.
    •  Let  denotes

      Unit
      body $P_{BS}^{Max}$

       denote the maximum transmit power of BS

    • Unit
      body $M=N\times K$

       is the number of all available RBs in each cell

    • Unit
      body $P_{BS}^{UE}$

       is the transmit power from BS to the active UE, and

    • Unit
      body $P_{BS}^{UE}=P_{BS}^{Max}\frac{N}{M}$

      .

2. Calculate DL C/I for all active UEs in all cells.

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• • Loop over all cells from  to j=1 to

    Unit
    body ${{N}_{cell}}$

     (the number of cells in the system area e.g. 57 for 19 sites with tri-sector antennas)
  • Loop over all active UEs from  tofrom 

    Unit
    body $k=1$

     to 

    Unit
    body $K$

  • For the k-th active UE in the j-th cell (i.e. 

    Unit
    body $U{{E}_{j,k}}$

    ) its C/I is denoted by

    Unit
    body $\frac{C(j,k)}{I(j,k)}$

    ,

3. Determine the throughput for each UE with its C/I according to the link-to-system level mapping.

4. Collect statistics.

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