The following describe the OFDMA DL algorithm presented in Section 9.7.
For i=1:# of snapshots
- Distribute sufficiently many UEs randomly throughout the system area such that to each cell within the HO margin of 3 dB the same number of users is allocated as active UEs.
- Calculate the pathloss from each UE to all cells and find the smallest pathloss
- Link the UE randomly to a cell to which the pathloss is within the smallest pathloss plus the HO margin of 3 dB
- Select K UEs randomly from all the UEs linked to one cell as active UEs. These active UEs will be scheduled during this snapshot.
- Note: a full load system is assumed, namely, all available resource blocks (RBs) will be allocated to active UEs. And each UE is scheduled with the same number of RBs. Thus, the BS transmit power per UE is fixed.
- Let denotes the maximum transmit power of BS
- is the number of all available RBs in each cell
- is the transmit power from BS to the active UE, and
- .
2. Calculate DL C/I for all active UEs in all cells.
- Loop over all cells from to (the number of cells in the system area e.g. 57 for 19 sites with tri-sector antennas)
- Loop over all active UEs from to
- For the -th active UE in the -th cell (i.e. ) its C/I is denoted by ,
3. Determine the throughput for each UE with its C/I according to the link-to-system level mapping.
4. Collect statistics.