Anchor | ||||
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1 Check rangeof application of the propagation model regarding time percentage, frequency, distance, and antenna height:
- Time percentage :
- 1% £
<pt £<50 % - Frequency : 30 MHz £
<f £<3 000 MHz - Distance :
- 1% £
- 0.001 km £
<d £<1000 km - Transmitter antenna height :
0 m < ht - 0.001 km £
- 0 m £
<ht £<3000 m - Receiver antenna height :
- 0 m £
- 1 m £
<
hr - 1 m £
- hr £
<3000 m
- hr £
2 Determination of lower and higher nominal percentages ptinf and ptsup:
...
4 If ht ³ 10 m: calculate field strength strength E(f= f, d, ht, hr, pt) 4) :
4.1) Calculation of the four following field strengths:
...
4.1.1) Calculate the dimensionless parameter k, function of the required transmitter height, ht:
(Eq. 218)
4.1.2) Determine from the following table the set of parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1 to be used according to nominal values of frequencies and time percentages:
Table 85: Parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1 Anchor T085 T085
Frequency | 100 MHz | 600 MHz | 2 000 MHz | ||||||
pt % | 50 | 10 | 1 | 50 | 10 | 1 | 50 | 10 | 1 |
a0 | 0.0814 | 0.0814 | 0.0776 | 0.0946 | 0.0913 | 0.0870 | 0.0946 | 0.0941 | 0.0918 |
a1 | 0.761 | 0.761 | 0.726 | 0.8849 | 0.8539 | 0.8141 | 0.8849 | 0.8805 | 0.8584 |
a2 | -30.444 | -30.444 | -29.028 | -35.399 | -34.160 | -32.567 | -35.399 | -35.222 | -34.337 |
a3 | 90.226 | 90.226 | 90.226 | 92.778 | 92.778 | 92.778 | 94.493 | 94.493 | 94.493 |
b0 | 33.6238 | 40.4554 | 45.577 | 51.6386 | 35.3453 | 36.8836 | 30.0051 | 25.0641 | 31.3878 |
b1 | 10.8917 | 12.8206 | 14.6752 | 10.9877 | 15.7595 | 13.8843 | 15.4202 | 22.1011 | 15.6683 |
b2 | 2.3311 | 2.2048 | 2.2333 | 2.2113 | 2.2252 | 2.3469 | 2.2978 | 2.3183 | 2.3941 |
b3 | 0.4427 | 0.4761 | 0.5439 | 0.5384 | 0.5285 | 0.5246 | 0.4971 | 0.5636 | 0.5633 |
b4 | 1.256E-7 | 7.788E-7 | 1.050E-6 | 4. |
323E-6 | 1. |
704E-7 | 5. |
169E-7 | 1.677E-7 | 3.126E-8 | 1.439E-7 | ||||||
b5 | 1.775 | 1.68 | 1.65 | 1.52 | 1.76 | 1.69 | 1.762 | 1.86 | 1.77 |
b6 | 49.39 | 41.78 | 38.02 | 49.52 | 49.06 | 46.5 | 55.21 | 54.39 | 49.18 |
b7 | 103.01 | 94.3 | 91.77 | 97.28 | 98.93 | 101.59 | 101.89 | 101.39 | 100.39 |
c0 | 5.4419 | 5.4877 | 4.7697 | 6.4701 | 5.8636 | 4.7453 | 6.9657 | 6.5809 | 6.0398 |
c1 | 3.7364 | 2.4673 | 2.7487 | 2.9820 | 3.0122 | 2.9581 | 3.6532 | 3.547 | 2.5951 |
c2 | 1.9457 | 1.7566 | 1.6797 | 1.7604 | 1.7335 | 1.9286 | 1.7658 | 1.7750 | 1.9153 |
c3 | 1.845 | 1.9104 | 1.8793 | 1.7508 | 1.7452 | 1.7378 | 1.6268 | 1.7321 | 1.6542 |
c4 | 415.91 | 510.08 | 343.24 | 198.33 | 216.91 | 247.68 | 114.39 | 219.54 | 186.67 |
c5 | 0.1128 | 0.1622 | 0.2642 | 0.1432 | 0.1690 | 0.1842 | 0.1309 | 0.1704 | 0.1019 |
c6 | 2.3538 | 2.1963 | 1.9549 | 2.2690 | 2.1985 | 2.0873 | 2.3286 | 2.1977 | 2.3954 |
d0 | 10 | 5.5 | 3 | 5 | 5 | 8 | 8 | 8 | 8 |
d1 | -1 | 1 | 2 | 1.2 | 1.2 | 0 | 0 | 0 | 0 |
4.1.3) Calculate the unblended to maximum value field strength, Eu, at the distance, d, and transmitting height, ht, as follows:
(Eq. 219)
where:
and:
and:
where:
where:
and:
4.1.4) Calculate the blended to the free space value of field strength, Eb, at the distance, d, and transmitting height, ht, as follows:
(Eq. 220)
...
Qinf =Qi (ptinf/100)
Qsup = Qi (ptsup /100)
Einf = E(f, d, ht, hr, ptinf)
...
The field-strength values given by the land curves and associated tabulations in this recommendation are for a reference receiving antenna at a height, R (m), representative of the height of the ground cover surrounding the receiving/mobile antenna, subject to a minimum height value of 10 m.
The SEAMCAT always assumes the height of local clutter R , depending on the propagation environment set in the model selection window:
Table 86: Default clutter height in the Anchor T086 T086
...
ITU-R P1546-1 model (when clutter height option not activated)
Selected environment | Assumed height of local clutter, m |
Rural | 10 |
Sub-urban | 10 |
Urban | 20 |
If the receiving antenna height, hr (m), is different from the assumed R value, as shown in Table 86 , a correction shall be added to the field strength taken from the curve.
...
where J(n) is given by :
(Eq. 227)
...
C0 = 2.515517
...
where:
Df: frequency-dependent term
=
km...
=
km...