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A17.7.1.3 Algorithm

A17.7.1.3 Algorithm

For calculation of the path loss according to Recommendation ITU-R P.1546-1 Annex 8 the following procedure is followed:

1 Check range of application of the propagation model regarding time percentage, frequency, distance, and antenna height: 

    • Time percentage :                           1% £< pt £< 50 %
    • Frequency :                                     30 MHz £< f £< 3 000 MHz
    • Distance :                                        0.001 km  £< d £< 1000 km
    • Transmitter antenna height :            0 m £< ht £< 3000 m
    • Receiver antenna height :               1 m £< hr £< 3000 m

 

Determination of lower and higher nominal percentages ptinf and ptsup:

If t < 10 then ptinf = 1 % and ptsup= 10 % else ptinf = 10 % and ptsup= 50 %

3 Determination of the lower and higher nominal frequencies :

If f < 600 MHz then finf = 100 MHz and fsup= 600 MHz else finf = 600 MHz and fsup= 2000 MHz

4 If ht ³ 10 m: calculate field strength E(f= f, d, ht, hr, pt) :

4.1) Calculation of the four following field strengths:

-              E(f= finf , d, ht, hr, ptinf)

-              E(f= fsup , d, ht, hr, ptinf)

-              E(f= finf , d, ht, hr, ptsup)

-              E(f= fsup , d, ht, hr, ptsup)

according to the procedure described in steps 4.1.1. to 4.1.4.

4.1.1) Calculate the dimensionless parameter k, function of the required transmitter height, ht:

                                              (Eq. 218)

4.1.2) Determine from the following table the set of parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1 to be used according to nominal values of frequencies and time percentages:

 

Table 85: Parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1

 

Frequency

100 MHz

600 MHz

2 000 MHz

pt %

50

10

1

50

10

1

50

10

1

a0

0.0814

0.0814

0.0776

0.0946

0.0913

0.0870

0.0946

0.0941

0.0918

a1

0.761

0.761

0.726

0.8849

0.8539

0.8141

0.8849

0.8805

0.8584

a2

-30.444

-30.444

-29.028

-35.399

-34.160

-32.567

-35.399

-35.222

-34.337

a3

90.226

90.226

90.226

92.778

92.778

92.778

94.493

94.493

94.493

b0

33.6238

40.4554

45.577

51.6386

35.3453

36.8836

30.0051

25.0641

31.3878

b1

10.8917

12.8206

14.6752

10.9877

15.7595

13.8843

15.4202

22.1011

15.6683

b2

2.3311

2.2048

2.2333

2.2113

2.2252

2.3469

2.2978

2.3183

2.3941

b3

0.4427

0.4761

0.5439

0.5384

0.5285

0.5246

0.4971

0.5636

0.5633

b4

1.256E-7

7.788E-7

1.050E-6

4.323E-6

1.704E-7

5.169E-7

1.677E-7

3.126E-8

1.439E-7

b5

1.775

1.68

1.65

1.52

1.76

1.69

1.762

1.86

1.77

b6

49.39

41.78

38.02

49.52

49.06

46.5

55.21

54.39

49.18

b7

103.01

94.3

91.77

97.28

98.93

101.59

101.89

101.39

100.39

c0

5.4419

5.4877

4.7697

6.4701

5.8636

4.7453

6.9657

6.5809

6.0398

c1

3.7364

2.4673

2.7487

2.9820

3.0122

2.9581

3.6532

3.547

2.5951

c2

1.9457

1.7566

1.6797

1.7604

1.7335

1.9286

1.7658

1.7750

1.9153

c3

1.845

1.9104

1.8793

1.7508

1.7452

1.7378

1.6268

1.7321

1.6542

c4

415.91

510.08

343.24

198.33

216.91

247.68

114.39

219.54

186.67

c5

0.1128

0.1622

0.2642

0.1432

0.1690

0.1842

0.1309

0.1704

0.1019

c6

2.3538

2.1963

1.9549

2.2690

2.1985

2.0873

2.3286

2.1977

2.3954

d0

10

5.5

3

5

5

8

8

8

8

d1

-1

1

2

1.2

1.2

0

0

0

0

 

4.1.3) Calculate the unblended to maximum value field strength, Eu, at the distance, d, and transmitting height, ht, as follows:

                                                                                        (Eq. 219)

where: 

and: 

and: 

where: 

 

where: 

 

and: 

 

4.1.4) Calculate the blended to the free space value of field strength, Eb, at the distance, d, and transmitting height, ht, as follows:

                                                                                    (Eq. 220)

where:

Efs is the free-space field strength

Efs = 106.9 - 20 log(d)   dB(μV/m)

pbb is a blend coefficient set to value 8.

4.2) Calculation of the field strength E(f, d, ht, hr, ptinf) using log-linear interpolation in frequency range:

                             E = Einf + (Esup - Einf) log(f/finf)/log(fsup/finf)     (dB(μV/m))                                  (Eq. 221)

where:

Einf:       E(f= finf , d, ht, hr, ptinf)

Esup:      E(f= fsup , d, ht, hr, ptinf)

 

4.3) Dual calculation for the field strength E(f, d, ht, hr, ptsup) using log-linear interpolation in frequency range:

                             E = Einf + (Esup - Einf) log(f/finf)/log(fsup/finf)     (dB(μV/m))                                  (Eq. 222)

where:

Einf:                       E(f= finf , d, ht, hr, ptsup)

Esup:                      E(f= fsup , d, ht, hr, ptsup)

4.4) Calculation of the field strength E(f, d, ht, hr, pt) using log-linear interpolation formula in time percentage range :

                  E = Esup (Qinf- Qt)/(Qinf- Qsup) + Einf(Qt - Qsup)/(Qinf- Qsup)     (dB(μV/m))                 (Eq. 223)     

Where: (Qi (x) being the inverse complementary cumulative normal distribution function):

Qt     = Qi (pt/100)

Qinf       =Qi (ptinf/100)

Qsup  = Qi (ptsup /100)

Einf    = E(f, d, ht, hr, ptinf)

Esup     =E(f, d, ht, hr, ptsup)

 

5 For a transmitting/base antenna height ht less than 10 m, determine the field strength for the required height and distance using following method

 

The procedure for extrapolating field strength at a required distance d km for values of ht in the range 0 m to 10 m is based on smooth-Earth horizon distances in km written as dH(h) = 4.1Öh, where h is the required value of transmitting/base antenna height ht in metres.

For d < dH(ht) the field strength is given by the 10 m height curve at its horizon distance, plus DE, where DE is the difference in field strengths on the 10 m height curve at distances d and the ht horizon distance.

For d ³ dH(ht) the field strength is given by the 10 m height curve at distance Dd beyond its horizon distance, where Dd is the difference between d and the ht horizon distance.

This may be expressed in the following formulae where E10 (d) is the field strength in dB(µV/m) calculated for transmitter antenna 10 m and for a distance d (km) according to the procedure described in step 4:

E = E10(dH(10)) + E10(d) - E10(dH(ht))                                             dB(µV/m)   d < dH(ht)                         

         =    E10(dH(10) + d - dH(ht))                                                dB(µV/m)   d ³ dH(ht)                         

If in the latter equation dH(10) + d - dH(ht) exceeds 1 000 km, even though d £ 1 000 km, E10 may be found from linear extrapolation for log(distance) of the curve, given by:

 

E10  =    Einf + (Esup - Einf) log(d/Dinf)/log(Dsup/Dinf)                        dB(µV/m)                                          

where:

Dinf:                        penultimate tabulation distance (km)

Dsup:                       final tabulation distance (km)

Einf:                        field strength at penultimate tabulation distance (dB(µV/m))

Esup:                       field strength at final tabulation distance (dBµV/m))

Note: this recommendation is not valid for distances greater than 1 000 km. This method should be used only for extrapolating for ht < 10 m.

 

6 If the receiving antenna height hr is not equal to the height of representative clutter at its location (denoted R), correct the field strength as follows:

The field-strength values given by the land curves and associated tabulations in this recommendation are for a reference receiving antenna at a height, R (m), representative of the height of the ground cover surrounding the receiving/mobile antenna, subject to a minimum height value of 10 m.

SEAMCAT always assumes the height of local clutter R , depending on the propagation environment set in the model selection window:

Table 86: Default clutter height in the ITU-R P1546-1 model (when clutter height option not activated)

 

Selected environment

Assumed height of local clutter, m

Rural

10

Sub-urban

10

Urban

20

 

If the receiving antenna height, hr (m), is different from the assumed R value, as shown in Table 86 , a correction shall be added to the field strength taken from the curve.

 

Where the receiving antenna is adjacent to land account should first be taken of the elevation angle of the arriving ray by calculating a modified representative clutter height R' (m), given by:

R'            =    R    (m)                                            for ht <= 6.5d + R                                     (Eq. 224)

               = (1 000 d R – 15 ht)/(1 000 d - 15 ) (m) for ht > 6.5d + R                                      (Eq. 225)

where ht is in metres and distance d is in km.

 

The value of R' must be limited if necessary such that it is not less than 1 m.

 

When the receiving antenna is in an urban environment the correction is then given by:

         Correction = (6.03) - J(n)                                               dB                   for hr < R

= K hr log(hr /R')                                             dB                   for hr ³ R                 (Eq. 226)

where J(n) is given by :

                                           (Eq. 227)

where:

           n                      =                          Knu Ö (hdif qclut)

           hdif                    =                            R' - hr         (m)

           q clut                  =                          arctan (hdif /27) (degree)

           K hr                   =                          3.2 + 6.2 log(f)

           Knu                   =                          0.0108 Ö f

           f                       =                          frequency (MHz)

Where the receiving antenna is adjacent to land in a rural environment the correction is given by the above equation (3) for all values of hr.

If the required distance is equal to or greater than d10, then again the correction for the required value of h2 should be calculated using above equation (2) with R' set to 10 m.

If the required distance is less than d10, then the correction to be added to the field strength E should be calculated using:

Correction         = 0.0                                         dB        d £ d (hr)                                   (Eq. 228)

                                    = (C10) log(d/dhr)/log(d10/dhr)         dB        dhr < d < d10              

where:

C10:       correction for the required value of hr at distance d10 using equation (2) with R' set to 10 m,

d10:       distance at which the path just has 0.6 Fresnel clearance for hr = 10 m
calculated as D06(f, ht, 10) as given in note 2

dhr:       distance at which the path just has 0.6 Fresnel clearance for the required value of hr calculated as D06(f, ht, hr) as given in note 2

 

This recommendation is not valid for receiving antenna heights, hr, less than 1 m.

 

7 Add a log-normal term G(sL) corresponding to the variability in the percentage of locations :

 

Values of standard deviation for digital systems having a bandwidth less than 1 MHz and for analogue systems are given as a function of frequency by:

                               sL = K + 1.6 log(f)          dB                                                               (Eq. 229)

where :

K          =          2.1 - for mobile systems in urban locations;

3.8 - for mobile systems in suburban locations or amongst rolling hills;

5.1 - for analogue broadcasting systems.

For digital systems having a bandwidth of 1 MHz or greater, a standard deviation of 5.5 dB should be used at all frequencies.

8 If necessary, limit the resulting field strength to the maximum value calculated as follows:

 

The field strength must not exceed a maximum value Emax given by:

  EMax = Efs                                               dB(mV/m)      for land paths

where Efs is the free space field strength for 1 kW e.r.p. given by:

                               Efs = 106.9 - 20 log(d)     (dB(mV/m))                                       (Eq. 230)

9 Convert field strength to path loss using following formula:

 

             Lb = 77.2 – E 20 log f     (dB)                                                  (Eq. 231)

where:

Lb: basic transmission loss (dB)

E: field strength in dB(mV/m) measured with a transmitting power of 1 W e.i.r.p.

f: frequency (MHz).

 

Note 1: The following approximation to the inverse complementary cumulative normal distribution function, Qi(x), is valid for 0.01 <= x <= 0.99 :

Qi(x) = T(x) –x(x)                     if x £ 0.5

Qi(x) = -{T(1-x) – x(1-x)}            if x > 0.5

where:

                                                 

            

                                                                       C0 = 2.515517

                                                                       C1 = 0.802853

                                                                       C2 = 0.010328

                                                                       D1 = 1.432788

                                                                       D2 = 0.189269

                                                                       D3 = 0.001308

Note 2: the path length which just achieves a clearance of 0.6 of the first Fresnel zone over a smooth curved Earth, for a given frequency and antenna heights ht and hr, is given approximately by:

                                                                                                                             

where:

                      Df:        frequency-dependent term

                     =                          km                                                                              

                     Dh:        asymptotic term defined by horizon distances

                     =                               km                                                                              

                        f:        frequency (MHz)

                  ht, hr:        antenna heights above smooth Earth (m)

In the above equations, the value of ht must be limited, if necessary, such that it is not less than zero. Moreover, the resulting values of D06 must be limited, if necessary, such that it is not less than 0.001 km.

Note 3: the case ht is less than zero described in the recommendation is not handled.

Note 4: no correction due to terrain clearance angle is implemented.

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