Anchor | ||||
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- Time percentage : 1% £
<= pt <= 50 pt £<50 % - Frequency : 30 MHz £
<= f £<= 3 3 000 MHz - Distance : 0.001 km £
<= d <= 1000 d £<1000 km - Transmitter antenna height : 0 m £
<= ht <= 3000 ht £<3000 m - Receiver antenna height : 1 m £
<= hr <= 3000 m hr £<3000 m
- Time percentage : 1% £
2 Determination of lower and higher nominal percentages ptinf and ptsup:
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4.1.1) Calculate the dimensionless parameter k, function of the required transmitter height, ht:
227218)
(Eq.4.1.2) Determine from the following table the set of parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1 to be used according to nominal values of frequencies and time percentages:
Table 8785: Parameters a0 to a3, b0 to b7, c0 to c6 and d0 to d1 Anchor T087T085T087 T085
Frequency | 100 MHz | 600 MHz | 2 000 MHz | ||||||
pt % | 50 | 10 | 1 | 50 | 10 | 1 | 50 | 10 | 1 |
a0 | 0.0814 | 0.0814 | 0.0776 | 0.0946 | 0.0913 | 0.0870 | 0.0946 | 0.0941 | 0.0918 |
a1 | 0.761 | 0.761 | 0.726 | 0.8849 | 0.8539 | 0.8141 | 0.8849 | 0.8805 | 0.8584 |
a2 | -30.444 | -30.444 | -29.028 | -35.399 | -34.160 | -32.567 | -35.399 | -35.222 | -34.337 |
a3 | 90.226 | 90.226 | 90.226 | 92.778 | 92.778 | 92.778 | 94.493 | 94.493 | 94.493 |
b0 | 33.6238 | 40.4554 | 45.577 | 51.6386 | 35.3453 | 36.8836 | 30.0051 | 25.0641 | 31.3878 |
b1 | 10.8917 | 12.8206 | 14.6752 | 10.9877 | 15.7595 | 13.8843 | 15.4202 | 22.1011 | 15.6683 |
b2 | 2.3311 | 2.2048 | 2.2333 | 2.2113 | 2.2252 | 2.3469 | 2.2978 | 2.3183 | 2.3941 |
b3 | 0.4427 | 0.4761 | 0.5439 | 0.5384 | 0.5285 | 0.5246 | 0.4971 | 0.5636 | 0.5633 |
b4 | 1.256E-7 | 7.788E-7 | 1.050E-6 | 4.323E-6 | 1.704E-7 | 5.169E-7 | 1.677E-7 | 3.126E-8 | 1.439E-7 |
b5 | 1.775 | 1.68 | 1.65 | 1.52 | 1.76 | 1.69 | 1.762 | 1.86 | 1.77 |
b6 | 49.39 | 41.78 | 38.02 | 49.52 | 49.06 | 46.5 | 55.21 | 54.39 | 49.18 |
b7 | 103.01 | 94.3 | 91.77 | 97.28 | 98.93 | 101.59 | 101.89 | 101.39 | 100.39 |
c0 | 5.4419 | 5.4877 | 4.7697 | 6.4701 | 5.8636 | 4.7453 | 6.9657 | 6.5809 | 6.0398 |
c1 | 3.7364 | 2.4673 | 2.7487 | 2.9820 | 3.0122 | 2.9581 | 3.6532 | 3.547 | 2.5951 |
c2 | 1.9457 | 1.7566 | 1.6797 | 1.7604 | 1.7335 | 1.9286 | 1.7658 | 1.7750 | 1.9153 |
c3 | 1.845 | 1.9104 | 1.8793 | 1.7508 | 1.7452 | 1.7378 | 1.6268 | 1.7321 | 1.6542 |
c4 | 415.91 | 510.08 | 343.24 | 198.33 | 216.91 | 247.68 | 114.39 | 219.54 | 186.67 |
c5 | 0.1128 | 0.1622 | 0.2642 | 0.1432 | 0.1690 | 0.1842 | 0.1309 | 0.1704 | 0.1019 |
c6 | 2.3538 | 2.1963 | 1.9549 | 2.2690 | 2.1985 | 2.0873 | 2.3286 | 2.1977 | 2.3954 |
d0 | 10 | 5.5 | 3 | 5 | 5 | 8 | 8 | 8 | 8 |
d1 | -1 | 1 | 2 | 1.2 | 1.2 | 0 | 0 | 0 | 0 |
4.1.3) Calculate the unblended to maximum value field strength, Eu, at the distance, d, and transmitting height, ht, as follows:
228219)
(Eq.where:
and:
and:
where:
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where:
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and:
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4.1.4) Calculate the blended to the free space value of field strength, Eb, at the distance, d, and transmitting height, ht, as follows:
229220)
(Eq.where:
Efs is the free-space field strength
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E = Einf + (Esup - Einf) log(f/finf)/log(fsup/finf) (dB(μV/m)) (Eq. 230221)
where:
Einf: E(f= finf , d, ht, hr, ptinf)
Esup: E(f= fsup , d, ht, hr, ptinf)
4.3) Dual calculation for the field strength E(f, d, ht, hr, ptsup) using log-linear interpolation in frequency range:
E = Einf + (Esup - Einf) log(f/finf)/log(fsup/finf) (dB(μV/m)) (Eq. 231222)
where:
Einf: E(f= finf , d, ht, hr, ptsup)
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E = Esup (Qinf- Qt)/(Qinf- Qsup) + Einf(Qt - Qsup)/(Qinf- Qsup) (dB(μV/m)) (Eq. 232223)
Where: (Qi (x) being the inverse complementary cumulative normal distribution function):
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Esup =E(f, d, ht, hr, ptsup)
5 For a transmitting/base antenna height ht less than 10 m, determine the field strength for the required height and distance using following method
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If in the latter equation dH(10) + d - dH(ht) exceeds 1 000 km, even though d <- £ 1 000 km, E10 may be found from linear extrapolation for log(distance) of the curve, given by:
E10 = Einf + (Esup - Einf) log(d/Dinf)/log(Dsup/Dinf) dB(µV/m)
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Note: this recommendation is not valid for distances greater than 1 000 km. This method should be used only for extrapolating for ht < 10 m.
6 If the receiving antenna height hr is not equal to the height of representative clutter at its location (denoted R), correct the field strength as follows:
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SEAMCAT always assumes the height of local clutter R , depending on the propagation environment set in the model selection window:
Table 86: Default clutter height in the ITU-R P1546-1 model (when clutter height option not activated) Anchor T088T086T088 T086
Selected environment | Assumed height of local clutter, m |
Rural | 10 |
Sub-urban | 10 |
Urban | 20 |
If the receiving antenna height, hr (m), is different from the assumed R value, as shown in Table 86 , a correction shall be added to the field strength taken from the curve.
Where the receiving antenna is adjacent to land account should first be taken of the elevation angle of the arriving ray by calculating a modified representative clutter height R' (m), given by:
R' = R (m) for ht <= 6.5d + R (Eq. 233224)
= (1 000 d R – 15 ht)/(1 000 d - 15 ) (m) for ht > 6.5d + R (Eq. 234225)
where ht is in metres and distance d is in km.
The value of R' must be limited if necessary such that it is not less than 1 m.
When the receiving antenna is in an urban environment the correction is then given by:
Correction = (6.03) - J(n) dB for dB for hr < R
= K hr log(hr /R') dB for hr ³ R (Eq. 235226)
where J(n) is given by :
236227)
(Eq.where:
n = Knu Ö (hdif qclut) - PLS. INSERT CORRECT FORMULA AND SYMBOL
hdif = R' - hr (m)
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Correction = 0.0 dB d ← £ d (hr) (Eq. 237228)
= (C10) log(d/dhr)/log(d10/dhr) dB dhr < d < d10
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dhr: distance at which the path just has 0.6 Fresnel clearance for the required value of hr calculated as D06(f, ht, hr) as given in note 2
This recommendation is not valid for receiving antenna heights, hr, less than 1 m.
7 Add a log-normal term G(sL) corresponding to the variability in the percentage of locations :
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sL = K + 1.6 log(f) dB (Eq. 238229)
where :
K = 2.1 - for mobile systems in urban locations;
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Efs = 106.9 - 20 log(d) (dB(mV/m)) (Eq. 239230)
9 Convert field strength to path loss using following formula:
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Lb = 77.2 – E 20 log f (dB) (Eq. 240231)
where:
Lb: basic transmission loss (dB)
E: field strength in dB(mV/m) measured with a transmitting power of 1 W e.i.r.p.
f: frequency (MHz).
Note 1: The following approximation to the inverse complementary cumulative normal distribution function, Qi(x), is valid for 0.01 <= x <= 0.99 :
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C0 = 2.515517
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where: Df: (km) (frequency
Df: frequency-dependent term
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= km
Dh: asymptotic term defined by horizon distances)
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= km
f: frequency (MHz)
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